Socket
Socket
Sign inDemoInstall

deterministic-split

Package Overview
Dependencies
4
Maintainers
1
Versions
5
Alerts
File Explorer

Advanced tools

Install Socket

Detect and block malicious and high-risk dependencies

Install

    deterministic-split

Deterministically choose between a number of options given a certain value.


Version published
Weekly downloads
60
decreased by-27.71%
Maintainers
1
Install size
39.2 kB
Created
Weekly downloads
 

Readme

Source

deterministic-split

Deterministically choose between a number of options given a certain value.

Ideal for A|B Testing.

When given a value, and any number of options will choose an option with equal probability of each option being chosen.
Will always return the same option for any given value and number of options.

const deterministicSplit = require('deterministic-split');

deterministicSplit('a value', 2) // Always returns 0
deterministicSplit('b value', 2) // Always returns 1
deterministicSplit('a value', 5) // Always returns 3

Use

deterministicSplit(value: string, options: array|number)
Array can include:

  • number: the weight of that option
  • string: the value to return when returning that option
  • object: an option containing a weight and a value to return

Example Use-case

I have many users, and many options to present the user.
I want to present the user only one option. I always want to present the same user the same option.
I'm unable to store which user has been presented which option.

deterministicSplit('fred', 3) // Fred always gets the second option

OR

deterministicSplit('fred', ['orange', 'yellow', 'red']) // Fred always gets 'yellow'

I want most users to see the normal color 'orange', and only a few to get the other two

// Most users will get 'yellow', as will fred
deterministicSplit('fred', [ 3, 1, 1 ])
deterministicSplit('fred', [{value: 'orange', weight: 3}, {value: 'yellow', weight: 1}, {value: 'red', weight: 1}])

But poor fred is often finding himself put in the same group of people.
I want to get a unique split for any given test.
To do this I can add a salt to my value.

deterministicSplit('fred' + 'whatColor', [ 'orange', 'yellow', 'red' ]) // Fred always gets orange
deterministicSplit('fred' + 'whatSize', [ 'big', 'medium', 'small' ]) // Fred always gets medium

Another situation might require passing a value that is not a string. In this case it must be nested inside an object.

I want to run different code depending on what option is chosen

deterministicSplit('fred' + 'whatFunction', [{
  value: () => console.log('Run Code A')
},{
  value: () => console.log('Run Code B')
} ]) // Returns the first function

Keywords

FAQs

Last updated on 25 Apr 2017

Did you know?

Socket for GitHub automatically highlights issues in each pull request and monitors the health of all your open source dependencies. Discover the contents of your packages and block harmful activity before you install or update your dependencies.

Install

Related posts

SocketSocket SOC 2 Logo

Product

  • Package Alerts
  • Integrations
  • Docs
  • Pricing
  • FAQ
  • Roadmap

Stay in touch

Get open source security insights delivered straight into your inbox.


  • Terms
  • Privacy
  • Security

Made with ⚡️ by Socket Inc