react-native-quick-layout

react-native-quick-layout

Why?

In this examle,I have a lot of textinput and have to exposure properties of member.So why not create TLayout component independently?

TLayout

In TLayout,We hava a lot different T to Show.

ILayout

In ILayout,the layout is divided into the upper and lower layout and the left and right layout

Install

npm i react-native-quick-layout --save

or use yarn

yarn add react-native-quick-layout

Usage

using ES6 modules and destructuring..

import {
  ILayout,
  TLayout,
} from 'react-native-quick-layout';

Examples

TLayout

const tstyle = StyleSheet.create({
  TContainer: {
    flex: 0.5,
    backgroundColor: 'yellow',
    width: 300,
  },
  mid: { backgroundColor: 'gray', flex: 1 },
  sub1: {
    backgroundColor: 'red',
    flex: 1,
  },
  sub2: {
    backgroundColor: 'yellow',
    flex: 1,
  },
  sub3: {
    backgroundColor: 'green',
    flex: 1,
  },
  text: {
    color: 'white',
    fontSize: 18
  },
});



    const tLayout = (
      <TLayout
        position={TLayout.Position.bottom}
        containerStyle={tstyle.TContainer}
        renderSub1={<View><Text>11111</Text></View>}
        
        renderSub2={<View><Text>22222</Text></View>}
        renderSub3={<View><Text>33333</Text></View>}
        sub1Style={tstyle.sub1}
        sub2Style={tstyle.sub2}
        sub1And2ContainerStyle={tstyle.mid}
        sud3ContainerStyle={tstyle.sub3}
      />
    );

ILayout

const istyle = StyleSheet.create({
  IContainer: {
    flex: 0.5,
    backgroundColor: 'yellow',
    width: 300,
  },
  sub1: {
    backgroundColor: 'red',
    flex: 1,
  },
  sub2: {
    backgroundColor: 'green',
    flex: 1,
  },
  text: {
    color: 'white',
    fontSize: 18
  },
});


    const iLayout = (
      <ILayout
        isLay={false}
        containerStyle={istyle.IContainer}
        sub1Style={istyle.sub1}
        sub2Style={istyle.sub2}
        renderSub1={<Text style={istyle.text}>试试改变"isLay"的值</Text>}
        renderSub2={<Text style={istyle.text}>我是renderSub2中的内容</Text>}
      />
    )

License

MIT