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Regular expressions for humans.
The human-regex package provides the classes StringRegex
and BytesRegex
which are subclasses of str
or bytes
, respectively. They contain methods and properties which can produce your regular expressions with readable code.
from human_regex import StringRegex as Sre
regex = Sre("match")
assert regex == "match"
regex = regex.not_preceded_by("element")
assert regex == "(?<!element)match"
regex = regex.named("my_group")
assert regex == "(?P<my_group>(?<!element)match)"
regex = Sre("match").not_preceded_by("element").named("my_group").optional
assert regex == "(?P<my_group>(?<!element)match)?"
Let's construct regular expressions for words ending in with the letter "c" and also for words starting with the letter "a":
from human_regex import StringRegex as Sre
word = Sre(r"\w").zero_or_more
assert word == r"\w*"
word_endswith_c = word.append("c").named("ends_with_c").prepend(r"\b").append(r"\b")
assert word_endswith_c == r"\b(?P<ends_with_c>\w*c)\b"
word_startswith_a = word.prepend("a").named("starts_with_a").prepend(r"\b").append(r"\b")
assert word_startswith_a == r"\b(?P<starts_with_a>a\w*)\b"
str
, bytes
StringRegex
and BytesRegex
are subclasses of str
or bytes
, respectively. They interoperate with these objects seamlessly. Here are some alternative ways how to construct the pattern from the previous example in the Overview section. Here we mix StringRegex
and str
instances:
from human_regex import StringRegex as Sre
word = Sre(r"\w")
word += "*"
assert word == r"\w*"
assert isinstance(word, Sre)
assert isinstance(word, str)
word_endswith_c: str = "".join((r"\b", "(?P<ends_with_c>", word, "c", ")", r"\b"))
word_endswith_c: Sre = Sre(word_endswith_c)
# same as:
word_endswith_c: Sre = Sre("").join((r"\b", "(?P<ends_with_c>", word, "c", ")", r"\b"))
word_endswith_c: Sre = Sre.concatenate((r"\b", "(?P<ends_with_c>", word, "c", ")", r"\b"))
re
Module's Functions and FlagsStringRegex
and BytesRegex
objects proxy the class re.RegexFlag
and all flags and functions of the built-in re
module (i.e. re.compile
, re.search
, etc.). These fuctions automatically take the StringRegex
or BytesRegex
instance object as their first argument:
from human_regex import StringRegex as Sre
import re # needed only for the assert statements below
assert Sre.RegexFlag is re.RegexFlag
sre = Sre("abc.")
# Use the proxied `re.compile` function of the StringRegex instance
# and the proxied flags on the StringRegex class
compiled = sre.compile(flags=Sre.IGNORECASE | Sre.DOTALL)
# same as:
# compiled = re.compile(sre, flags=re.IGNORECASE | re.DOTALL)
assert isinstance(compiled, re.Pattern)
text = "abc\nABCd\n\Abc"
found = sre.findall(text, flags=Sre.IGNORECASE | Sre.DOTALL)
# same as:
# found = re.findall(sre, text, flags=re.IGNORECASE | re.DOTALL)
assert found == ["abc\n", "ABCd"]
Every method demonstated with StringRegex
is available on BytesRegex
and is applicable to bytes
objects, rather than str
objects:
from human_regex import StringRegex as Sre, BytesRegex as Bre
import re # needed only for the assert statements below
string_re = Sre("abc.").named("my_group")
string_pattern = string_re.compile(flags=Sre.IGNORECASE | Sre.DOTALL)
assert isinstance(string_pattern, re.Pattern)
bytes_re = Bre(b"abc.").named(b"my_group")
bytes_pattern = bytes_re.compile(flags=Bre.IGNORECASE | Bre.DOTALL)
assert isinstance(bytes_pattern, re.Pattern)
assert string_pattern.flags == 50 # includes the implicit Sre.UNICODE flag
assert bytes_pattern.flags == 18 # bytes patterns cannot use the UNICODE flag
assert (Bre.IGNORECASE | Bre.DOTALL | Bre.UNICODE).value == 50
Iterating over str
instances will yield individual string characters, but iterating over bytes
instances will yield instances of int
.
some_strings = "abc"
assert tuple(some_strings) == ("a", "b", "c")
s: str = "".join(some_strings) # iterates over "abc" and joins its elements
assert s == "abc"
some_integers = b"abc"
assert tuple(some_integers) == (97, 98, 99)
b: bytes = b"".join(some_integers)
# will raise a TypeError because elements of the iterable b"abc"
# are the integers 97, 98, 99 but bytes.join
# expects instances of bytes-like objects
StringRegex
and BytesRegex
are subclasses of str
and bytes
respectively, so they inherit this behavior. You can use a StringRegex
instance as an iterable of string characters, but iterating over a BytesRegex
instance will yield integers. Methods BytesRegex.concatenate
and BytesRegex.join
, both of which use bytes.join
internally, cannot work with iterables of integers. They expect iterables of bytes-like objects.
from human_regex import BytesRegex as Bre
# as long as the iterable yields bytes-like objects, everyting is fine:
some_bytes = (b"a", Bre(b"b"), b"c")
assert Bre.concatenate(some_bytes) == Bre(b"abc")
some_integers = Bre(b"abc")
b = Bre.concatenate(some_integers) # will raise a TypeError
# because the elements of Bre(b"abc") are integers,
# rather than bytes-like objects:
assert tuple(Bre(b"abc")) == (97, 98, 99)
# we would have to convert the integers to string characters and encode them to bytes:
b = Bre.concatenate(map(lambda i: str.encode(chr(i)), some_integers))
StringRegex
and BytesRegex
differ slightly in their private class variables, but their public methods and properties have all been inherited from the human_regex.bases.general_regex.GeneralRegexBase
class. Thus, the documentation of the StringRegex
or BytesRegex
's inherited public methods and properties is to be looked up there. For methods proxied from the built-in re module or inherited from str
, or bytes
, look in the Python's standard library documentation.
FAQs
Regular expressions for humans
We found that human-regex demonstrated a healthy version release cadence and project activity because the last version was released less than a year ago. It has 1 open source maintainer collaborating on the project.
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