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    lunardate

A Chinese Calendar Library in Pure Python


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A Chinese Calendar Library in Pure Python

Chinese Calendar: http://en.wikipedia.org/wiki/Chinese_calendar

Usage

    >>> LunarDate.fromSolarDate(1976, 10, 1)
    LunarDate(1976, 8, 8, 1)
    >>> LunarDate(1976, 8, 8, 1).toSolarDate()
    datetime.date(1976, 10, 1)
    >>> LunarDate(1976, 8, 8, 1).year
    1976
    >>> LunarDate(1976, 8, 8, 1).month
    8
    >>> LunarDate(1976, 8, 8, 1).day
    8
    >>> LunarDate(1976, 8, 8, 1).isLeapMonth
    True

    >>> today = LunarDate.today()
    >>> type(today).__name__
    'LunarDate'

    >>> # support '+' and '-' between datetime.date and datetime.timedelta
    >>> ld = LunarDate(1976,8,8)
    >>> sd = datetime.date(2008,1,1)
    >>> td = datetime.timedelta(days=10)
    >>> ld-ld
    datetime.timedelta(0)
    >>> (ld-sd).days
    -11444
    >>> ld-td
    LunarDate(1976, 7, 27, 0)
    >>> (sd-ld).days
    11444
    >>> ld+td
    LunarDate(1976, 8, 18, 0)
    >>> td+ld
    LunarDate(1976, 8, 18, 0)
    >>> ld2 = LunarDate.today()
    >>> ld < ld2
    True
    >>> ld <= ld2
    True
    >>> ld > ld2
    False
    >>> ld >= ld2
    False
    >>> ld == ld2
    False
    >>> ld != ld2
    True
    >>> ld == ld
    True
    >>> LunarDate.today() == LunarDate.today()
    True
    >>> before_leap_month = LunarDate.fromSolarDate(2088, 5, 17)
    >>> before_leap_month.year
    2088
    >>> before_leap_month.month
    4
    >>> before_leap_month.day
    27
    >>> before_leap_month.isLeapMonth
    False
    >>> leap_month = LunarDate.fromSolarDate(2088, 6, 17)
    >>> leap_month.year
    2088
    >>> leap_month.month
    4
    >>> leap_month.day
    28
    >>> leap_month.isLeapMonth
    True
    >>> after_leap_month = LunarDate.fromSolarDate(2088, 7, 17)
    >>> after_leap_month.year
    2088
    >>> after_leap_month.month
    5
    >>> after_leap_month.day
    29
    >>> after_leap_month.isLeapMonth
    False

Limits

this library can only deal with year from 1900 to 2099 (in chinese calendar).

See also

FAQs


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