ormlambda

ormMySQL

This ORM is designed to connect with a MySQL server, facilitating the management of various database queries. Built with flexibility and efficiency in mind, this ORM empowers developers to interact with the database using lambda functions, allowing for concise and expressive query construction.

Creating your first lambda query

Initialize MySQLRepository

from decouple import config
from ormlambda.databases.my_sql import MySQLRepository

USERNAME = config("USERNAME")
PASSWORD = config("PASSWORD")
HOST = config("HOST")


database = MySQLRepository(user=USERNAME, password=PASSWORD, database="sakila", host=HOST)

Select all columns

from models.address import AddressModel

result = AddressModel(database).select()

The result var will be of type tuple[Address, ...]

Select multiples tables

Once the AddressModel class is created, we will not only be able to access all the information in that table, but also all the information in all the tables that have foreign keys related to it."

from ormlambda import ConditionType
from models.address import AddressModel


result = AddressModel(database).where(lambda x: (x.City.Country, ConditionType.REGEXP, r"^[aA]")).select(
    lambda address: (
        address,
        address.City,
        address.City.Country,
    ),
)

The result var will be of type tuple[tuple[Address], tuple[City], tuple[Country]].

If we were used select_one method, we retrieved tuple[Address, City, Country].

Filter by where condition

result = AddressModel(database).where(lambda x: 10 <= x.address_id <= 30).select()

Additionally, we can filter by others tables. For example, we can return all addresses for each city where country_id = 87 (Spain)

result = AddressModel(database).where(lambda x: x.City.Country.country_id  == 87).select()

We can also return Address, City or Country if needed.

result = AddressModel(database).where(lambda x: x.City.Country.country_id == 87).select(lambda x: (x, x.City, x.City.Country))

Pass variables to the where method

Since we generally work with lambda methods, I often have to work with bytecode to retrieve the name of the string variables. For this reason, it's imperative that we map these variables to replace them with the actual values.

LOWER = 10
UPPER = 30
AddressModel(database).where(lambda x: LOWER <= x.address_id <= UPPER, LOWER=LOWER, UPPER=UPPER).select()

That solution is somewhat awkward and not very clean, but it's necessary for automating queries.

Writable methods INSERT, UPDATE, DELETE

The easiest way to add or delete data in your database is by using its appropiate methods. You just need to instantiate an object with the data and pass it to the method

Insert

address = Address(address_id=1, address="C/ ...", phone="XXXXXXXXX", postal_code="28026")

AddressModel(database).insert(address)

Update

You can use either the properties of the same object or str values.

AddressModel(database).where(lambda x: x.address_id == 1).update(
    {
        Address.phone: "YYYYYYYYY",
        Address.postal_code: "28030",
    }
)

AddressModel(database).where(lambda x: x.address_id == 1).update(
    {
        "phone": "YYYYYYYYY",
        "postal_code": "28030",
    }
)

Delete

AddressModel(database).where(lambda x: x.address_id == 1).delete()

Table Map

The most important aspect when creating classes to map database tables is to consider the importance of typing the variables that should behave as columns. In other words, variables that are typed will be those that are passed to the class constructor. This is why both __table_name__ and variables that reference foreign classes, are not given a specific data tpye.

For example, imagine you have three Table in your database: Addres, City and Country. Each of them has its own Foreing keys.

Address has a FK relationship with City.

City has a FK relationship with Country.

The easiest way to map your tables is:

from datetime import datetime

from ormlambda import (
    Column,
    Table,
    BaseModel,
    ForeignKey,
)
from ormlambda.common.interfaces import IStatements_two_generic, IRepositoryBase


class Country(Table):
    __table_name__ = "country"

    country_id: int = Column[int](is_primary_key=True)
    country: str
    last_update: datetime


class Address(Table):
    __table_name__ = "address"

    address_id: int = Column[int](is_primary_key=True)
    address: str
    address2: str
    district: str
    city_id: int
    postal_code: str
    phone: str
    location: str
    last_update: datetime = Column[datetime](is_auto_generated=True)

    City = ForeignKey["Address", City](__table_name__, City, lambda a, c: a.city_id == c.city_id)


class City(Table):
    __table_name__ = "city"

    city_id: int = Column[int](is_primary_key=True)
    city: str
    country_id: int
    last_update: datetime

    Country = ForeignKey["City", Country](__table_name__, Country, lambda ci, co: ci.country_id == co.country_id)

Once created, you need to create a Model for each Table

class CountryModel(BaseModel[Country]):
    def __new__[TRepo](cls, repository: IRepositoryBase[TRepo]):
        return super().__new__(cls, Country, repository)


class AddressModel(BaseModel[Address]):
    def __new__[TRepo](cls, repository: IRepositoryBase[TRepo]):
        return super().__new__(cls, Address, repository)


class CityModel(BaseModel[City]):
    def __new__[TRepo](cls, repository: IRepositoryBase[TRepo]):
        return super().__new__(cls, City, repository)

Creating complex queries with lambda

We can use various methods such as where, limit, offset, order, etc...

Filter using where method

To retrieve all Address object where the fk reference to the City table, and the fk reference to the Country table have a country_id value greater or equal than 50, ordered in descending order, then:

result = (
    AddressModel(database)
    .order(lambda a: a.address_id, order_type="DESC")
    .where(lambda x: x.City.Country.country_id >= 50)
    .select(lambda a: (a))
)

Also you can use ConditionType enum for regular expressions and get, for example, all rows from a different table where the Country name starts with A, limited to 100:

address, city, country = (
    AddressModel(database)
    .order(lambda a: a.address_id, order_type="DESC")
    .where(lambda x: (x.City.Country, ConditionType.REGEXP, r"^[A]"))
    .limit(100)
    .select(
        lambda a: (
            a,
            a.City,
            a.City.Country,
        )
    )
)


for a in address:

    print(a.address_id)

for c in city:
    print(c.city_id)

for co in country:
    print(co.country)

Transform Table objects into Iterable object

In the example above, we see that the result var returns a tuple of tuples. However, we can simplify the result var when needed by passing flavour attribute in select method to get a tuple of the specified data type.

result = (
    a_model
    .where(lambda x: (x.City.Country, ConditionType.REGEXP, r"^[A]"))
    .limit(100)
    .select(
        lambda a: (
            a.address_id,
            a.City.city_id,
            a.City.Country.country_id,
            a.City.Country.country,
        ),
        flavour=dict,
    )
)

with this approach, we will obtain a dictionary where the key will be the concatenation between the selected table name and the column name specified in the lambda function, to avoid overwritting data from tables that sharing column names.