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unmatcher tries to solve the following problem:
*Given a regular expression, find any string that matches the expression.*
Why? Mostly just because. But one possible application is to generate test data for string processing functions.
Status
|Version| |License| |Build Status|
.. |Version| image:: https://badge.fury.io/py/unmatcher.png
:alt: PyPI package version
:target: http://badge.fury.io/py/unmatcher
.. |License| image:: https://img.shields.io/pypi/l/unmatcher.svg?style=flat
:target: https://github.com/Xion/unmatcher/blob/master/LICENSE
:alt: License
.. |Build Status| image:: https://secure.travis-ci.org/Xion/unmatcher.png
:alt: Build Status
:target: http://travis-ci.org/Xion/unmatcher
Most typical elements of regexes are supported:
* multipliers: ``*``, ``+``
* capture groups: ``|``, ``( )`` (including backreferences)
* character classes (``\d|\w|\s`` etc.) and character sets (``[]``)
API
~~~
``unmatcher`` module exposes a single ``reverse`` function.
It takes a regular expression - either in text or compiled form - and returns a random string that matches it::
>>> import unmatcher
>>> print unmatcher.reverse(r'\d')
7
Additional arguments can be provided, specifying predefined values for capture groups
inside the expression. Use positional arguments for numbered groups (``'\1'``, etc.)::
>>> import unmatcher
>>> print unmatcher.reverse(r'<(\w+)>.*</\1>', 'h1')
<h1>1NLNVlrOT4YGyHV3vD7cHvrAl8OHVWDPKgmaE4gUsctboyFYUx</h1>
and keyword arguments for named groups::
>>> import unmatcher
>>> print unmatcher.reverse('(?P<foo>\w+)__(?P=foo)', foo='bar')
bar__bar
Note that a predefined value is *not* validated against actual subexpression for the capture group.
FAQs
Regular expression reverser for Python
We found that unmatcher demonstrated a healthy version release cadence and project activity because the last version was released less than a year ago. It has 1 open source maintainer collaborating on the project.
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