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Given two arrays A and B, returns what should be added, updated and / or removed when going from A to B
Given two arrays A and B, returns what should be added, updated and / or removed to transform A into B. In optimal linear time.
import diff from "darray";
const [add, update, remove] = diff([1, 2, 3], [2, 3, 4]);
console.log(add); // [4]
console.log(update); // []
console.log(remove); // [1]
import diff from "darray";
const before = [
{
id: "1",
label: "Do this"
},
{
id: "2",
label: "Do that"
}
];
const after = [
{
id: "2",
label: "Nop, do this instead"
},
{
id: "3",
label: "Do that thing"
},
{
id: "4",
label: "Do this last thing"
}
];
const [add, update, remove] = diff(
before,
after,
todo => todo.id,
(t1, t2) => t1.label === t2.label
);
console.log(add);
/*[
{
id: "3",
label: "Do that thing"
},
{
id: "4",
label: "Do this last thing"
}
];*/
console.log(update);
/*[
{
id: "2",
label: "Nop, do this instead"
}
];*/
console.log(remove);
/*[
{
id: "1",
label: "Do this"
}
];*/
export declare function diff<T>(
oldArray: Array<T>,
newArray: Array<T>,
identity?: (element: T) => any,
equivalent?: (oldElement: T, newElement: T) => boolean
): readonly [T[], T[], T[]];
export declare function hasDiff<T>(
oldArray: Array<T>,
newArray: Array<T>,
identity?: (element: T) => any,
equivalent?: (oldElement: T, newElement: T) => boolean
): boolean;
export default diff;
identity
function should provide a unique and stable identity for each array element. By default, this function returns the element itself.equivalent
function will be called on each pair (old element, new element) with the same identity, to know if the new element should be marked as an update or not. By default, this function performs a strict equality check.FAQs
Given two arrays A and B, returns what should be added, updated and / or removed when going from A to B
We found that darray demonstrated a not healthy version release cadence and project activity because the last version was released a year ago. It has 0 open source maintainers collaborating on the project.
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