regex-recursion

regex-recursion

This is an official plugin for Regex+ that adds support for recursive matching up to a specified max depth N, where N can be between 2 and 100. Generated regexes are native JavaScript RegExp instances, and support all regular expression features except numbered backreferences (support could be added in future versions).

Recursive matching is added to a regex via one of the following (the recursion depth limit is provided in place of N):

• (?R=N) — Recursively match the entire regex at this position.
• \g<name&R=N> or \g<number&R=N> — Recursively match the contents of the group referenced by name or number at this position.
  • The \g subroutine must be within the referenced group.

Multiple uses of recursion within the same pattern are allowed if they are non-overlapping. Named captures and backreferences are supported within recursion, and are independent per depth level. So e.g. groups.name on a match object is the value captured by group name at the top level of the recursion stack.

Install and use

npm install regex regex-recursion

import {regex} from 'regex';
import {recursion} from 'regex-recursion';

const re = regex({plugins: [recursion]})`…`;

Using a global name (no import)

<script src="https://cdn.jsdelivr.net/npm/regex@4.4.0/dist/regex.min.js"></script>
<script src="https://cdn.jsdelivr.net/npm/regex-recursion@4.2.0/dist/regex-recursion.min.js"></script>
<script>
  const {regex} = Regex;
  const {recursion} = Regex.plugins;

  const re = regex({plugins: [recursion]})`…`;
</script>

Examples

Match an equal number of two different subpatterns

Anywhere within a string

// Matches sequences of up to 50 'a' chars followed by the same number of 'b'
const re = regex({plugins: [recursion]})`a(?R=50)?b`;
re.exec('test aaaaaabbb')[0];
// → 'aaabbb'

As the entire string

const re = regex({plugins: [recursion]})`^
  (?<balanced>
    a
    # Recursively match just the specified group
    \g<balanced&R=50>?
    b
  )
$`;
re.test('aaabbb'); // → true
re.test('aaabb'); // → false

Notice the ^ and $ anchors outside of the recursive subpattern.

Match balanced parentheses

// Matches all balanced parentheses up to depth 50
const parens = regex({flags: 'g', plugins: [recursion]})`
  \( ( [^\(\)] | (?R=50) )* \)
`;

'test ) (balanced ((parens))) () ((a)) ( (b)'.match(parens);
/* → [
  '(balanced ((parens)))',
  '()',
  '((a))',
  '(b)'
] */

Following is an alternative that matches the same strings, but adds a nested quantifier. It then uses an atomic group to prevent this nested quantifier from creating the potential for catastrophic backtracking.

const parens = regex({flags: 'g', plugins: [recursion]})`
  \( ( (?> [^\(\)]+ ) | (?R=50) )* \)
`;

This matches sequences of non-parens in one step with the nested + quantifier, and avoids backtracking into these sequences by wrapping it with an atomic group (?>…). Given that what the nested quantifier + matches overlaps with what the outer group can match with its * quantifier, the atomic group is important here. It avoids exponential backtracking when matching long strings with unbalanced parens.

Atomic groups are provided by the base regex library.

Match palindromes

Match palindromes anywhere within a string

const palindromes = regex({flags: 'gi', plugins: [recursion]})`
  (?<char> \w )
  # Recurse, or match a lone unbalanced char in the middle
  ( (?R=15) | \w? )
  \k<char>
`;

'Racecar, ABBA, and redivided'.match(palindromes);
// → ['Racecar', 'ABBA', 'edivide']

In the example above, the max length of matched palindromes is 31. That's because it sets the max recursion depth to 15 with (?R=15). So, depth 15 × 2 chars (left + right) for each depth level + 1 optional unbalanced char in the middle = 31. To match longer palindromes, the max recursion depth can be increased to a max of 100, which would enable matching palindromes up to 201 characters long.

Match palindromes as complete words

const palindromeWords = regex({flags: 'gi', plugins: [recursion]})`\b
  (?<palindrome>
    (?<char> \w )
    ( \g<palindrome&R=15> | \w? )
    \k<char>
  )
\b`;

'Racecar, ABBA, and redivided'.match(palindromeWords);
// → ['Racecar', 'ABBA']

Notice the \b word boundaries outside of the recursive subpattern.