a.require

a.require for Node.js

Require manager for Node.js. Can execute same function as system require and some else

Usage

Install with npm

npm install a.require 

Configurate at first

var _require = require('a.require');
_require.init({root: __dirname});

Try it

Load Node.js module

var fs = _require('fs')

Load javascript file from root location

var simple = _require('./simple')

For example you has some file structure like this

application$ /private/tmp
├── app
│   ├── helpers
│   ├── modules
│   │   ├── core
│   │   │   └── models
│   │   │       └── settings.js
│   │   └── frontend
│   │       ├── controllers
│   │       │   └── index.js
│   │       ├── dao
│   │       │   └── posts.js
│   │       ├── models
│   │       │   └── posts.js
│   │       └── modules
│   │           ├── admin
│   │           │   ├── controllers
│   │           │   │   └── index.js
│   │           │   └── models
│   │           │       └── profile.js
│   │           └── auth
│   │               └── controllers
│   │                   └── users.js
│   └── utils
│       └── request.js
└── config
    └── app.yaml

Get index.js controller from frontend

var indexFrontend = _require("controller:app.frontend:index")

Get post.js model from frontend

var postModelFrontend = _require("model:app.frontend:posts")

Get posts.js dao from frontend

_require.init({names: {'dao': 'dao'}});
var postsDAOFrontend = _require("dao:app.frontend:posts")

Get index.js controller from frontend/admin

var indexAuthFrontend = _require("controller:app.frontend.auth:index")

Get request from utils

var request = _require("app:./utils/request")
var request = _require("./app/utils/request")

Extra

Get full path to file

var fullname = _require.path("config:app.yaml");

License

May be freely distributed under the MIT license

See LICENSE file

Copyright (c) 2013 - Sumskoy Andrew [e-mail]