A solution of https://leetcode.com/problems/word-break-ii/:
import type { ITrie } from '@algorithm.ts/trie'
import { Trie, lowercaseIdx } from '@algorithm.ts/trie'
const trie: ITrie<string, number> = new Trie<string, number>({
SIGMA_SIZE: 26,
idx: lowercaseIdx,
mergeNodeValue: (_x, y) => y,
})
export function wordBreak(text: string, wordDict: string[]): string[] {
if (text.length <= 0) return []
trie.clear()
for (let i = 0; i < wordDict.length; ++i) {
const word = wordDict[i]
trie.set(word, i)
}
const N = text.length
const results: string[] = []
const collect: number[] = []
dfs(0, 0)
return results
function dfs(cur: number, pos: number): void {
if (pos === N) {
results.push(
collect
.slice(0, cur)
.map(x => wordDict[x])
.join(' '),
)
return
}
for (const { end, val } of trie.findAll(text, pos, text.length)) {
collect[cur] = val
dfs(cur + 1, end)
}
}
}
A solution of https://leetcode.com/problems/word-search-ii/
import { Trie, lowercaseIdx } from '@algorithm.ts/trie'
class CustomTrie<E extends unknown[] | string, V> extends Trie<E, V> {
public getSnapshot(): { ch: Uint32Array[]; values: Array<V | undefined> } {
return {
ch: this._ch,
values: this._values,
}
}
}
const trie = new CustomTrie<string, number>({
SIGMA_SIZE: 26,
idx: lowercaseIdx,
mergeNodeValue: (x, _y) => x,
})
export function findWords(board: string[][], words: string[]): string[] {
const N = words.length
const R = board.length
const C = board[0].length
if (N <= 0 || R <= 0 || C <= 0) return []
trie.clear()
for (let i = 0; i < N; ++i) trie.set(words[i], i)
const boardCode: number[][] = []
for (let r = 0; r < R; ++r) {
const codes: number[] = []
for (let c = 0; c < C; ++c) codes[c] = board[r][c].charCodeAt(0) - 97
boardCode[r] = codes
}
const visited: boolean[][] = new Array(R)
for (let r = 0; r < R; ++r) visited[r] = new Array(C).fill(false)
let matchedWordCount = 0
const isWordMatched: boolean[] = new Array(N).fill(false)
const { ch, values } = trie.getSnapshot()
for (let r = 0; r < R; ++r) {
for (let c = 0; c < C; ++c) {
dfs(0, r, c)
}
}
const results: string[] = words.filter((_w, i) => isWordMatched[i])
return results
function dfs(u: number, r: number, c: number): void {
if (visited[r][c] || matchedWordCount === N) return
const u2: number = ch[u][boardCode[r][c]]
if (u2 === 0) return
const val = values[u2]
if (val !== undefined && !isWordMatched[val]) {
isWordMatched[val] = true
matchedWordCount += 1
}
visited[r][c] = true
if (r > 0) dfs(u2, r - 1, c)
if (c + 1 < C) dfs(u2, r, c + 1)
if (r + 1 < R) dfs(u2, r + 1, c)
if (c > 0) dfs(u2, r, c - 1)
visited[r][c] = false
}
}