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babel-plugin-transform-bigint

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babel-plugin-transform-bigint

*Update:* Now it can convert a code using BigInt into a code using JSBI (https://github.com/GoogleChromeLabs/jsbi). It will try to detect when an operator is used for bigints, not numbers. This will not work in many cases, so please use JSBI directly onl


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babel-plugin-transform-bigint

Update: Now it can convert a code using BigInt into a code using JSBI (https://github.com/GoogleChromeLabs/jsbi). It will try to detect when an operator is used for bigints, not numbers. This will not work in many cases, so please use JSBI directly only if you know, that the code works only with bigints.

An example from https://github.com/GoogleChromeLabs/babel-plugin-transform-jsbi-to-bigint:

Input using native BigInts:

const a = BigInt(Number.MAX_SAFE_INTEGER);
const b = 2n;

a + b;
a - b;
a * b;
a / b;
a % b;
a ** b;
a << b;
a >> b;
a & b;
a | b;
a ^ b;

-a;
~a;

a === b;
a < b;
a <= b;
a > b;
a >= b;

a.toString();
Number(a);

Compiled output using JSBI:

const a = JSBI.BigInt(Number.MAX_SAFE_INTEGER);
const b = JSBI.BigInt(2);
JSBI.add(a, b);
JSBI.subtract(a, b);
JSBI.multiply(a, b);
JSBI.divide(a, b);
JSBI.remainder(a, b);
JSBI.exponentiate(a, b);
JSBI.leftShift(a, b);
JSBI.signedRightShift(a, b);
JSBI.bitwiseAnd(a, b);
JSBI.bitwiseOr(a, b);
JSBI.bitwiseXor(a, b);
JSBI.unaryMinus(a);
JSBI.bitwiseNot(a);
JSBI.equal(a, b);
JSBI.lessThan(a, b);
JSBI.lessThanOrEqual(a, b);
JSBI.greaterThan(a, b);
JSBI.greaterThanOrEqual(a, b);
a.toString();
JSBI.toNumber(a);

¡ It is buggy !

Usage:

  1. Create a file test.js:
// floor(log2(n)), n >= 1
function ilog2(n) {
  let i = 0n;
  while (n >= 2n**(2n**i)) {
    i += 1n;
  }
  let e = 0n;
  let t = 1n;
  while (i >= 0n) {
    let b = 2n**i;
    if (n >= t * 2n**b) {
      t *= 2n**b;
      e += b;
    }
    i -= 1n;
  }
  return e;
}

// floor(sqrt(S)), S >= 0, https://en.wikipedia.org/wiki/Methods_of_computing_square_roots#Babylonian_method
function sqrt(S) {
  let e = ilog2(S);
  if (e < 2n) {
    return 1n;
  }
  let f = e / 4n + 1n;
  let x = (sqrt(S / 2n**(f * 2n)) + 1n) * 2n**f;
  let xprev = x + 1n;
  while (xprev > x) {
    xprev = x;
    x = (x + S / x) / 2n;
  }
  return xprev;
}

function squareRoot(value, decimalDigits) {
  return (sqrt(BigInt(value) * 10n**(BigInt(decimalDigits) * 2n + 2n)) + 5n).toString();
}


  1. Use babel:
npm install --save https://github.com/Yaffle/babel-plugin-transform-bigint
npm install --save-dev @babel/core @babel/cli
npx babel --plugins=babel-plugin-transform-bigint test.js > test-transformed.js
  1. create a file test.html.
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8" />
  <script src="node_modules/big-integer/BigInteger.js"></script>
  <script src="node_modules/babel-plugin-transform-bigint/runtime.js"></script>
  <script src="test-transformed.js"></script>
  <script>
    document.addEventListener("DOMContentLoaded", function (event) {
      const form = document.querySelector("form");
      const update = function () {
        const value = form.value.value;
        const digits = Number(form.digits.value);
        const s = squareRoot(value, digits);
        form.output.value = '√' + value +  ' ≈ ' + s.slice(0, 0 - digits - 1) + '.' + s.slice(0 - digits - 1, -1) + '…';
      };
      form.oninput = function () {
        update();
      };
      update();
    }, false);
  </script>
  <style>
    output {
      overflow-wrap: break-word;
    }
  </style>
</head>
<body>
  <form>
    <div>
      <label for="value">Value:</label>
      <input id="value" name="value" type="number" min="2" step="1" value="2" />
    </div>
    <div>
      <label for="digits">Number of decimal digits:</label>
      <input id="digits" name="digits" type="number" min="1" step="1" value="100" />
    </div>
    <div>
      <output id="output" name="output" for="value digits" tabindex="0"></output>
    </div>
  </form>
</body>
</html>
  1. Open test.html in a web browser.

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Package last updated on 18 Mar 2019

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