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[5.0.0]
To sum up, the big change in 5.0 is a Typescript change related to Map
that is typed closer to the JS object. This is a huge change for TS users, but do not impact the runtime behavior. (see Improve TypeScript definition for Map
for more details)
Other breaking changes are:
Released in 5.0.0-rc.1
Map.of('k', 'v')
: use Map([ [ 'k', 'v' ] ])
or Map({ k: 'v' })
Collection.isIterable
: use isIterable
directlyCollection.isKeyed
: use isKeyed
directlyCollection.isIndexed
: use isIndexed
directlyCollection.isAssociative
: use isAssociative
directlyCollection.isOrdered
: use isOrdered
directlyOrdererMap
and OrderedSet
hashCode implementation has been fixedReleased in 5.0.0-rc.1
Fix issue implementation of hashCode
for OrdererMap
and OrderedSet
where equal objects might not return the same hashCode
.
Changed in #2005
Released in 5.0.0-beta.5
Range with undefined
would end in an infinite loop. Now, you need to define at least the start and end values.
If you need an infinite range, you can use Range(0, Infinity)
.
Released in 5.0.0-beta.1
Immutable does not export a default object containing all it's API anymore.
As a drawback, you can not immport Immutable
directly:
- import Immutable from 'immutable';
+ import { List, Map } from 'immutable';
- const l = Immutable.List([Immutable.Map({ a: 'A' })]);
+ const l = List([Map({ a: 'A' })]);
If you want the non-recommanded, but shorter migration path, you can do this:
- import Immutable from 'immutable';
+ import * as Immutable from 'immutable';
const l = Immutable.List([Immutable.Map({ a: 'A' })]);
Map
Released in 5.0.0-beta.1
If you do use TypeScript, then this change does not impact you : no runtime change here. But if you use Map with TypeScript, this is a HUGE change ! Imagine the following code
const m = Map({ length: 3, 1: 'one' });
This was previously typed as Map<string, string | number>
and return type of m.get('length')
or m.get('inexistant')
was typed as string | number | undefined
.
This made Map
really unusable with TypeScript.
Now the Map is typed like this:
MapOf<{
length: number;
1: string;
}>
and the return type of m.get('length')
is typed as number
.
The return of m.get('inexistant')
throw the TypeScript error:
Argument of type '"inexistant"' is not assignable to parameter of type '1 | "length"
This is a minor BC for TS users, so if you want to keep the old definition, you can declare you Map like this:
const m = Map<string, string | number>({ length: 3, 1: 'one' });
You might want to declare a wider definition, you can type your Map like this:
type MyMapType = {
length: number;
1: string | null;
optionalProperty?: string;
};
const m = Map<MyMapType>({ length: 3, 1: 'one' });
Keep in mind that the MapOf
will try to be consistant with the simple TypeScript object, so you can not do this:
Map({ a: 'a' }).set('b', 'b');
Map({ a: 'a' }).delete('a');
Like a simple object, it will only work if the type is forced:
Map<{ a: string; b?: string }>({ a: 'a' }).set('b', 'b'); // b is forced in type and optional
Map<{ a?: string }>({ a: 'a' }).delete('a'); // you can only delete an optional key
Map
methods implemented ?For now, only get
, getIn
, set
, update
, delete
, remove
, toJS
, toJSON
methods are implemented. All other methods will fallback to the basic Map
definition. Other method definition will be added later, but as some might be really complex, we prefer the progressive enhancement on the most used functions.