node-relation

node-relation

This module helps you manage string, numbers, object as a group. Check the code.

import { Relationship } from 'node-relation'

let state = new Relationship().to('a', 'b')
state.nodes // ['a', 'b']

state = state.to('b', 'c')
state.nodes // ['a', 'b', 'c']

state = state.to('c', 'd')
state.from('c').nodes // ['c', 'd']

state = state.to('d', 'a')
state.from('c').nodes // ['a', 'b', 'c', 'd']

Install

You can download in npm node-relation.

npm install node-relation

How to use

Browser (esnext)

import { Relationship } from 'https://cdn.jsdelivr.net/npm/node-relation@5.x.x/+esm'

Node.js

import { Relationship } from 'node-relation'

const state = new Relationship().to('a', 'b', 'c')

Methods

The data inside the instance is immutable. The method does not modify the data inside, it returns the result of the calculation as a new instance.

to(source: T, ...targets: T[]): Relationship

Creates a new refer between nodes, and returns it as a Relationship instance. This is one-sided relationship between both nodes.

const state = new Relationship().to('language', 'English', 'Korean', 'Japanese')

# state
language ─> English
language ─> Korean
language ─> Japanese

both(a: T, ...b: T[]): Relationship

Creates a new relationship between nodes, and returns it as a new Relationship instance. Both nodes will know each other.

const A = new Relationship().to('language', 'English', 'Korean', 'Japanese')
const B = A.both('English', 'US', 'France', 'Italy')

# A
language ─> English
language ─> Korean
language ─> Japanese

# B
language ─> English
English <─> US
English <─> France
English <─> Italy
language ─> Korean
language ─> Japanese

all(...nodes: T[]): Relationship

Creates a new relationship between all each other nodes, and returns it as a new Relationship instance. All nodes will know each others.

const state = new Relationship().all('john', 'harris', 'richard')

john <─> harris
harris <─> richard
richard <─> john

from(source: T, depth?: number = -1): Relationship

Only the nodes that are related to the node received by the parameter are filtered and returned in a new Relationship instance. You can control calculation depth relationship with depth parameter. If depth parameter are negative, it's will be calculate all relationship between nodes in instance. Depth parameter default value is -1.

let state = new Relationship()
  .to('language', 'English', 'Korean', 'Japanese')
  .both('English', 'US', 'France', 'Italy')

state.from('language').nodes // language, English, Korean, Japanese, US, France, Italy
state.from('English').nodes // English, US, France, Italy

where(filter: (node: T, i: number, array: T[]) => boolean, depth?: number = -1): Relationship

Returns a new relationship instance with only nodes that meet the conditions.

const state = new Relationship()
  .both('English', 'US', 'France', 'Italy')

state.where((v) => v === 'English').nodes // English, US, France, Italy

without(...nodes: T[]): T[]

Returns the remaining nodes except those received as parameters from the current relationship instance.

const state = new Relationship()
  .to('language', 'English', 'Korean', 'Japanese')

state.from('language').nodes // language, English, Korean, Japanese
state.from('language').without('language') // English, Korean, Japanese

unlinkTo(source: T, ...targets: T[]): Relationship

Deletes the relationship between nodes and returns it as a new Relationship instance. This is one-sided cut off between both nodes.

let state = new Relationship()
  .to('a', 'b', 'c')

state = state.unlinkTo('a', 'b')
state.nodes // a, c

unlinkBoth(a: T, ...b: T[]): Relationship

Deletes the relationship between nodes and returns it as a new Relationship instance. Both nodes will cut off each other.

let state = new Relationship()
  .both('a', 'b', 'c')

state = state.unlinkBoth('a', 'b')
state.nodes // a, c

drop(...nodes: T[]): Relationship

Delete the node. If the node associated with the deleted node is isolated, it is deleted together. Returns the result with a new Relationship instance.

let state = new Relationship()
  .to('a', 'b', 'c')

state = state.drop('a')
state.nodes // empty

let stateB = new Relationship()
  .to('a', 'b')
  .to('b', 'c')

stateB = stateB.drop('b')
stateB.nodes // empty

let stateC = new Relationship()
  .to('a', 'b')
  .to('b', 'c')
  .to('c', 'a')

stateC = stateC.drop('b')
stateC.nodes // a, c

has(node: T): boolean

Returns whether the instance contains that node.

const state = new Relationship()
  .to('a', 'b', 'c')

const exists = state.has('a') // true

hasAll(...nodes: T[]): boolean

Returns whether the instance contains all of its nodes.

const state = new Relationship()
  .to('a', 'b', 'c')

const existsAll = state.hasAll('a', 'b') // true

weight(node: T, log?: boolean = false): number

Returns how many nodes are related to the node received by the parameter.

const state = new Relationship()
  .to('a', 'd')
  .to('b', 'd')
  .to('c', 'd')

const weight = state.weight('d') // 3

weights(log?: boolean = false, normalize?: boolean = false, toScale?: boolean = false): Map<T, number>

Returns the weight of all nodes. Check the weight method.

const state = new Relationship()
  .to('a', 'd')
  .to('b', 'd')
  .to('c', 'd')
  .to('d', 'a')

// Map<[['a', 4], ['b', 0], ['c', 0], ['d', 4]]>
const weights = state.weights()

// Map<[['a', 1], ['b', 0], ['c', 0], ['d', 1]]>
const normalizedWeights = state.weights(false, true)

entry(node: T, log?: boolean = false): number

Returns how many nodes are related to the node received by the parameter.

const state = new Relationship()
  .to('a', 'b')
  .to('a', 'c')
  .to('a', 'd')

const entry = state.entry('a') // 3

entries(log?: boolean = false, normalize?: boolean = false, toScale?: boolean = false): Map<T, number>

Returns the entry value of all nodes. Check the entry method.

const state = new Relationship()
  .to('a', 'b')
  .to('a', 'c')
  .to('a', 'd')
  .to('b', 'a')

// Map<[['a', 4], ['b', 4], ['c', 0], ['d', 0]]>
const entries = state.entries()

// Map<[['a', 1], ['b', 1], ['c', 0], ['d', 0]]>
const normalizedEntries = state.entries(false, true)

depth(source: T, target: T, log?: boolean = false): number

Returns the found minimum depth to between source to target.

const state = new Relationship()
  .to('a', 'b')
  
state.depth('a', 'b') // 1
state.depth('b', 'a') // Infinity

distance(a: T, b: T, log?: boolean = false): number

Returns the found minimum distance to between both nodes. This is same as Math.min(this.depth(a, b), this.depth(b, a))

const state = new Relationship()
  .to('a', 'b')
  .to('b', 'c')

state.distance('b', 'a') // 1
state.distance('a', 'c') // 2

merge(...datasets: RelationData[]): Relationship

Merge a relation dataset with this instance, and returns it as a new Relationship instance. If there is a non-overlapping dataset, It will be append to instance.

const A = state.to('user-a', 'user-b')
const B = state.to('user-c', 'user-d')
const C = A.merge(B.dataset)

C.nodes // user-a, user-b, user-c, user-d

raw(node: T): T|undefined

This method for instance that useEqual options. It returns a original value from node parameter. It will be useful when using between returned Map from nodeset, oneHot, label getters and weights method.

const useEqual = true
const state = new Relationship(undefined, useEqual).to({ name: 'a' }, { name: 'b' })
const weights = state.weights()

weights.get({ name: 'b' })
// undefined. because 'weights' map instance doesn't using equal system.

const raw = state.raw({ name: 'b' })
weights.get(raw) // 1

clear(): void

Destroy the data in the instance. It is used for garbage collector.

constructor(dataset?: RelationData[], useEqual?: boolean = false): Relationship

You can pass dataset parameter to init this instance. The RelationData is type of 2-dimensional tuple array. Check dataset getter description.

const state = new Relationship([ ['a', ['b', 'c', 'd']] ])
const clone = new Relationship(state.dataset) 

If you want ignore strict references to variables, You can use the useEqual option. This helps you treat other objects as the same variable.

const useEqual = true
let state = new Relationship(null, useEqual)

state = state.to({ a: 1 }, { a: 2 })
state = state.to({ a: 1 }, { a: 3 })
state.nodes // { a: 1 }, { a: 2 }, { a: 3 }

(getter) dataset: RelationData[]

Returns as 2-dimensional array of relationships between nodes in the instance. Relationships are returned to saveable data-type(json).

const state = new Relationship().to('a', 'b').to('b', 'c', 'd')
state.dataset // [ ['a', ['b']], ['b', ['c', 'd']] ]

(getter) nodes: T[]

Get all nodes from the instance.

const state = new Relationship().to('a', 'b').to('b', 'c')
state.nodes // a, b, c

(getter) children: T[]

Get all children nodes without primary from the instance.

const a = new Relationship().to('a', 'b').to('b', 'c')
a.from('a').children // b, c

const b = a.both('d', 'e')
b.from('d').children // d, e

(getter) nodeset: Set<T>

Get all nodes as Set object from the instance.

const state = new Relationship().to('a', 'b').to('b', 'c')
state.nodeset // Set<['a', 'b', 'c']>

(getter) oneHot: Map<T, number[]>

Get all nodes as one-hot vectors from the instance. It could be used as dataset for machine learning.

const state = new Relationship().to('a', 'b').to('b', 'c')
const vectors = state.oneHot

vectors // Map<[['a', [1, 0, 0]], ['b', [0, 1, 0]], ['c', [0, 0, 1]]]>
Array.from(vectors.values()) // [[1, 0, 0], [0, 1, 0], [0, 0, 1]]

(getter) zeroVector: number[]

Get a 1-dimensional vector that was filled 0. The vector's size are same as nodes length of instance. This is useful for representing data that does not belong to anything. It could be used as dataset for machine learning.

const state = new Relationship().to('a', 'b').to('b', 'c')

const vectors = state.oneHot
const zeroVector = state.zeroVector // [0, 0, 0]
const allVectors = [zeroVector, ...vectors.values()]

(getter) label: Map<T, number>

Get all nodes as labeled vector from the instance. It could be used as dataset for machine learning.

const state = new Relationship().to('a', 'b').to('b', 'c')
const vector = state.label

vector // Map<[['a', 1], ['b', 2], ['c', 3]]>
Array.from(vector.values()) // [1, 2, 3]

(getter) clusters: T[][]

Returns the clustering models of this instance in the form of a two-dimensional array.

let state = new Relationship().to('a', 'b', 'c').to('d', 'e')
state.clusters // [[a, b, c], [d, e]]

state = state.to('e', 'a')
state.clusters // [[a, b, c, d, e]]

(getter) reverse: Relationship

Returns the instance in which the relationship of the node is reversed.

const state = new Relationship().to('a', 'b').to('b', 'c')

state.reverse.from('c').nodes // [a, b, c]

Try it simply

Applying (Advanced usage, with Typescript)

// The data structure what you want
// {
//   'server-a': [userA, userB],
//   'server-b': [userC]
// }

import { Relationship } from 'node-relation'

type ServerName = 'server-a' | 'server-b'
class User {
  ...
}

const userA = new User
const userB = new User
const userC = new User

let state: Relationship<ServerName|User> = new Relationship

state = state.to('server-a', userA, userB)
state = state.to('server-b', userC)

console.log( state.from('server-b').without('server-b') ) // userC

import { RawRelationship } from 'node-relation'

const sentence = 'what will the fat cat sit on'
const words = sentence.split(' ')

const state = new RawRelationship<string>()

words.forEach((word, i) => {
  const next = words[i+1]
  if (next) {
    state.to(word, next)
  }
})

const oneHot = state.oneHot // Map<[['what', [1,0,0,0,0,0,0]], ['will', [0,1,0,0,0,0,0]], ...]>
const oneHotVectors = Array.from(oneHot.values())

const label = state.label // Map<[['what', 1], ['will', 2], ...]>
const labels = Array.from(label.values())

Migration 3.x.x to 4.x.x

Check readme