requireDir()
Node helper to require()
directories. The directory's files are examined,
and each one that can be require()
'd is require()
'd and returned as part
of a hash from that file's basename to its exported contents.
Example
Given this directory structure:
dir
+ a.js
+ b.json
+ c.coffee
+ d.txt
requireDir('./dir')
will return the equivalent of:
{ a: require('./dir/a.js')
, b: require('./dir/b.json')
}
And if CoffeeScript has been registered via require('coffee-script/register')
,
c.coffee
will also be returned. Any extension registered with node will work the same way without any additional configuration.
Installation
npm install require-dir
Note that this package is not requireDir
— turns out that's already
taken! ;)
Usage
Basic usage that examines only directories' immediate files:
var requireDir = require('require-dir');
var dir = requireDir('./path/to/dir');
You can optionally customize the behavior by passing an extra options object:
var dir = requireDir('./path/to/dir', {recurse: true});
Options
recurse
: Whether to recursively require()
subdirectories too.
(node_modules
within subdirectories will be ignored.)
Default is false.
duplicates
: By default, if multiple files share the same basename, only the
highest priority one is require()
'd and returned. (Priority is determined by
the order of require.extensions
keys, with directories taking precedence
over files if recurse
is true.) Specifying this option require()
's all
files and returns full filename keys in addition to basename keys.
Default is false.
E.g. in the example above, if there were also an a.json
, the behavior would
be the same by default, but specifying duplicates: true
would yield:
{ a: require('./dir/a.js')
, 'a.js': require('./dir/a.js')
, 'a.json': require('./dir/a.json')
, b: require('./dir/b.json')
, 'b.json': require('./dir/b.json')
}
filter
: Apply a filter on the filename before require-ing. For example, ignoring files prefixed with dev
in a production environment:
requireDir('./dir', {
filter: function (fullPath) {
return process.env.NODE_ENV !== 'production' && !fullPath.match(/$dev/);
}
})
mapKey
: Apply a transform to the module base name after require-ing. For example, uppercasing any module names:
requireDir('./dir', {
mapKey: function (value, baseName) {
return baseName.toUpperCase();
}
})
mapValue
: Apply a transform to the value after require-ing. For example, uppercasing any text exported:
requireDir('./dir', {
mapValue: function (value, baseName) {
return typeof value === 'string' ? value.toUpperCase() : value;
}
})
Tips
If you want to require()
the same directory in multiple places, you can do
this in the directory itself! Just make an index.js
file with the following:
module.exports = require('require-dir')();
And don't worry, the calling file is always ignored to prevent infinite loops.
TODO
It'd be awesome if this could work with the regular require()
, e.g. like a
regular require()
hook. Not sure that's possible though; directories are
already special-cased to look for an index
file or package.json
.
An ignore
option would be nice: a string or regex, or an array of either or
both, of paths, relative to the directory, to ignore. String paths can be
extensionless to ignore all extensions for that path. Supporting shell-style
globs in string paths would be nice.
Currently, basenames are derived for directories too — e.g. a directory named
a.txt
will be returned as a
when recursing — but should that be the case?
Maybe directories should always be returned by their full name, and/or maybe
this behavior should be customizable. This is hopefully an edge case.
License
MIT. © 2012-2015 Aseem Kishore.