test-fixture
Copy test fixtures to a temp dir and get resolved file paths.
Why?
I am tired of writing these:
path.resolve(__dirname, 'test', 'fixtures')
,tmp.dir(callback)
,fse.copy(fixtures, dir)
path.join(fixtures, 'some-file.js')
EVERY DAY!
So, I got this.
Install
$ npm i test-fixture -D
Usage
const {copy, resolve} = require('test-fixture')()
;(async () => {
await copy()
console.log(resolve('foo.js'))
})
fixtures(...paths): {resolve, copy}
- paths
Array<path>
to define the root paths of the fixtures, which is similar as
Defines the root of the fixture
const path = require('path')
const fixturesRoot = path.resolve(projectRoot, 'test', 'fixtures')
path.resolve(fixturesRoot, ...args)
arguments | base (dir of test fixtures) |
---|
undefined | test/fixtures |
'a' | test/fixtures/a |
'a' , 'b' | test/fixtures/a/b |
'/path/to' (absolute) | /path/to |
'/path/to' (absolute), 'a' | /path/to/a |
Actually, the base
is path.resolve('text/fixtures', path...)
await copy(to?)
- to?
path=
the destination folder where the test fixtures will be copied to. If not specified, a temporary directory will be used.
Copy the test fixtures into another directory.
resolve(...paths)
Resolves the paths to get the path of the test fixtures
After .copy()
ed, it will resolve paths based on the destination dir.
If not, it will use the base dir. But never use both of them simultaneously.
/path/to/<base>
|-- a.js
/path/to/<to>
|-- a.js
Without copying
const {resolve} = fixtures(base)
resolve('a.js')
Using .copy()
const {copy, resolve} = fixtures(base)
await copy('/path/to')
resolve('a.js')
License
MIT