Pipable
pipe operation in python
Quick Start
Create the Pipe Object
- instantiate with the
Pipe
class
from pipable import Pipe
list = Pipe(list)
"abc" | list
Pipe Object is Partial with Infix Operator
- at the core Pipe create partial function while overriding it's
|
operator - instantiate Pipe object like the built-in
functools.partial
- preceding output will be assigned to the last positional argument of the Pipe object
square = Pipe(pow, exp=2)
3 | square
Since that Pipe appends preceding output to the last positional argument,
assigning 1st argument with keyword will raise exception.
This behave the same as functools.partial
base2 = Pipe(pow, 2)
3 | base2
base2 = Pipe(pow, base=2)
3 | base2
Using Decorator
@Pipe
decorator transforms function into Pipe object- preceding output will be assigned to the last positional argument
- instantiate Pipe decorated function similar to creating partial
@Pipe
def hi(name: str) -> str:
return f"hi {name}"
"May" | hi
@Pipe
def power(base: int, exp: int) -> int:
return base ** exp
2 | power(3)
2 | power(exp=3)
2 | power(base=3)
Passing Variable Length Arguments
- use
>>
operator to pass-in variable length arguments
@Pipe
def kebab(*args):
return "-".join(args)
["a", "b"] >> kebab
- use
<<
operator to pass variable length keyword arguments
@Pipe
def concat(**kwargs):
return ", ".join([f"{k}-{v}" for k, v in kwargs.items()])
dict(b="boy", c="cat") << concat
- refer the docs for details
Motivation
Pipe operation is a handy feature in functional programming. It allows us to:
- write more succinct and readable code
- create less variables
- easily create new function by chaining other functions
However it's still a missing feature in Python as of 2023. This package try to mimic pipe operation by overriding the bitwise-or operator, and turn any function into pipable partial.
There are packages, such as pipe take the similar approach. It works great with iterables, and create pipe as iterator, ie. open pipe). However, I simply want to take preceding expression as an input argument of the current function then execute it, ie. close pipe. It leads to the creation of this package.
FAQ
How can I assign value to the first argument?
use a wrapper function
square = Pipe(lambda x: pow(x, 2))
3 | square
Can I create open pipe?
Pipe
only create closed pipe, ie. execute the function after piping with the |
operator. You may consider other solutions such as:
- pipe, which create open pipe for iterators
- Coconut, a python variant that embrace functional programming
Can I append the preceding output at the beginning of the argument list?
Put the preceding output as the 1st argument of a wrapper function
def kebab(*args):
return "-".join(*args)
'a' | Pipe(kebab, 'b', 'c')
@Pipe
def wrapper(first, others):
return kebab(first, *others)
'a' | wrapper(others=['b', 'c'])
Need Help?
github issue
posts