Huge News!Announcing our $40M Series B led by Abstract Ventures.Learn More
Socket
Sign inDemoInstall
Socket

wait4it

Package Overview
Dependencies
Maintainers
1
Alerts
File Explorer

Advanced tools

Socket logo

Install Socket

Detect and block malicious and high-risk dependencies

Install

wait4it

Wait until a certain TCP port is available

  • 0.2.1
  • PyPI
  • Socket score

Maintainers
1

python-wait4it

Test PyPi License

Wait-For-It Python module, that waits until a certain TCP port is available.

Based on the idea behind the well-known wait-for-it script, but created mainly as a Python package to be used on other Python applications, services or modules, instead of being mainly a CLI tool.

Installing

Package is available at PyPi, so you can install it with pip install wait4it - or from sources with python setup.py install.

Usage

from wait4it import wait_for, WaitForTimeoutError

# This should return instantly (if you have connection)
wait_for(host="google.com", port=80)

# This should fail in 5 seconds
try:
    wait_for(host="google.com", port=12345, timeout=5)
except TimeoutError:
    # Actually will raise custom WaitForTimeoutError exception, but inherits from TimeoutError (except on Python2)
    print("Failed! (as expected)")

# This should return False in 15 seconds
wait_for(host="google.com", port=12345, raise_error=False)

# Normally you will want to check for a port in localhost (e.g. a MySQL/MariaDB database).
# This can be done directly like:
wait_for(3306)

# The exceptions include the failing host/port
try:
    wait_for(host="google.com", port=12345)
except WaitForTimeoutError as ex:
    assert ex.host == "google.com"
    assert ex.port == 12345

wait_for_pass decorator

It works similarly to wait_for, but if the considered exceptions are raised on the decorated function, it will re-run until it runs without raising these errors, or until the given retries limit is reached.

The following example will randomly raise ZeroDivisionError in the function divide_by_random, which runs 10 times. If fails more than twice, the exception will be thrown outside the function.

from random import randint
from wait4it import wait_for_pass

@wait_for_pass(ZeroDivisionError, retries=2)
def divide_by_random(n=10):
    d = randint(0, 1)
    print("Gonna divide", n, "/", d)
    return n / d

for _ in range(10):
    r = divide_by_random()
    print("Got result:", r)

If retries is set to 0, the function will run forever until it passes without raising exceptions.

wait_for_pass also allows a parameter retries_delay, which can be used to define a delay, in seconds, between failed function executions.

Dependencies & Compatibility

Not external dependencies are required. Compatible (tested with) Python 2.7, 3.4, 3.5, 3.6, 3.7, 3.8 - under Linux.

Changelog

  • 0.2.1 - Add retries_delay parameter to wait_for_pass
  • 0.1.2 - Fix wait_for_pass decorator not looping indefinitely when retries=0
  • 0.1.1 - Add wait_for_pass decorator
  • 0.0.1 - Initial release

TODO

  • Set retries limit on wait_for
  • Set timeout on wait_for_pass

Keywords

FAQs


Did you know?

Socket

Socket for GitHub automatically highlights issues in each pull request and monitors the health of all your open source dependencies. Discover the contents of your packages and block harmful activity before you install or update your dependencies.

Install

Related posts

SocketSocket SOC 2 Logo

Product

  • Package Alerts
  • Integrations
  • Docs
  • Pricing
  • FAQ
  • Roadmap
  • Changelog

Packages

npm

Stay in touch

Get open source security insights delivered straight into your inbox.


  • Terms
  • Privacy
  • Security

Made with ⚡️ by Socket Inc