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Exposes a way to enforce an interface on classes.
To enforce an interface, first create a new Interface
and pass it the function names that you want to enforce.
const MyInterface = new Interface('myMethodA', 'myMethodB')
Next, just make your class extend from the interface. Make sure you call super()
within your class's constructor.
class MyClass extends MyInterface {
constructor () {
super()
}
myMethodA () {
// ...implementation goes here
}
}
Now, whenever you try to instantiate MyClass
, the interface will be enforced.
let instance = new MyClass()
// throws a new error with the message:
// 'The following function(s) need to be implemented for class MyClass: myMethodB'
Of course, the interface is enforced on all subclasses as well.
class MySubClass extends MyClass {
constructor () {
super()
}
myMethodA () {
// override 'myMethodA'
}
}
let instance = new MySubClass()
// still throws an error with the message:
// 'The following function(s) need to be implemented for class MyClass: myMethodB'
Interfaces can be enforced for classes defined the old way too.
var inherits = require('util').inherits
var MyInterface = new Interface('myMethodA', 'myMethodB', 'myMethodC')
function MyClass () {
MyInterface.call(this)
}
MyClass.prototype.myMethodA = function () {
// implementation
}
function MySubClass () {
MyClass.call(this)
}
// inherit prototype of parent class
inherits(MySubClass, MyClass)
MySubClass.prototype.myMethodB = function () {
// implementation
}
var instance = new MySubClass()
// throws an error with the message:
// 'The following function(s) need to be implemented for class MyClass: myMethodC'
FAQs
Enforce an interface on classes
We found that interface demonstrated a not healthy version release cadence and project activity because the last version was released a year ago. It has 2 open source maintainers collaborating on the project.
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